Last updated: January 7, 2019

Work & Energy transfer in close hydraulic circuit.

See the diagram and you will find effort piston is moved S1 distance which is much greater than load piston S2.

As we know know, Work done = Force X displacement,

W = F X S.

According to our previous example,

F1 = 100 kg

F2= 1000 kg

A1 = 10 cm²

A2 = 100 cm²

p = 10 kg/

let by an 100 kg efforts piston 1 displaced (S1) 10 cm, so volume displaced will be, Area X displacement.

V = 10 x 10 = 100 cm³

Same volume will be transferred in the load piston, so liquid rises in load side cylinder will be,

S2 = V/A2

S2 = 100/100 = 1 cm

Now, work done in efforts piston,

W1 = F1 X S1

W1 = 100 x 10 = 1000

&, work done in load piston,

W2 = F2 X S2

W2 = 1000 x 1 = 1000.

W1 = W2. That’s mean work on both the piston is same only we are multiplying the force not creating energy for more work. Similarly, we can multiply the pressure.

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